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3.7v to 1.5v converter | 1.5v to 5v boost converter circuit

3.7V lithium-ion battery with a 5V charger can potentially lead to overcharging and, in turn, damage the battery or, in extreme cases.
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3.7v to 1.5v converter | 1.5v to 5v boost converter circuit

3.7v to 1.5v converter circuit- Electronic Project


This is the voltage boost converter of the module that provides a 5V DC stable. voltage output at various inputs of the ranges between 1.5V to 5V. This small tiny circuit boosts the voltage level or provides the amplified stabilized 5V output.

For the different input ranges, it consumes a different amount of current flow to produce a balanced output. While using this module one must comply with the following of the conditions. Input voltage cannot be greater than the nominal voltage otherwise, it shall burn out the module.The input power supply must be greater than the output power, otherwise, the output of the voltage will be less than the nominal voltage.

Conversion from lower to higher voltage is not that difficult as we have already learned about the AC to DC of the converter. But, this circuit is about DC to DC of the conversion. To increase the input voltage at the output load, the circuit diagram commonly known as a voltage booster is used. As the name implies, it takes the input voltage or with the help of some components transforms that voltage into high voltage. The circuit diagram can be made using different methods like inductors, capacitors, semiconductor switches, etc. But, for efficient output, some voltage of the regulator ICs are also available in the electronic market. Hence, we shall use one of them in our project. With the IC ME2108A33P, this circuit diagram also uses the Schottky diode SS14.

Diagram of 5v to 1.5v converter:

3.7v to 1.5v converter

Hardware Required for this Project:

You can get the components from any of the sites below:

  1. BC547 Transistor [See Buy Click Amazon]
  2. 10k Ohm Resistor [See Buy Click Amazon]

*Please note: These are affiliate links. I may make a commission if you buy the components through these links. I would appreciate your support in this way!

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Working Principle of 1.5v to 5v boost converter circuit :

In this circuit diagram of the 3.7V to 5V Boost Converter, the major component is ME2108A33P IC. The internal structure of this IC is so promising or that’s why it requires very few components for its external circuitry. The IC has three pins. It uses a maximum switching frequency of 180KHz. This IC could deliver 400mA output current flow if the input voltage is 3.0V and the output voltage is fixed at 5.0V. On the input side, we have connected the inductor. By changing the value of the Inductor and output Capacitor you could adjust the output voltage range. The Schottky diode SS14 is also wired at the input side, usually used to prevent the circuit from reverse polarity. At the output, the capacitors are there to observe the readings.

This Circuit diagram is designed to convert 230V AC to 1.5V DC, As we know in order to obtain low voltage from high voltage AC we need to use a Stepdown transformer. Here 230V of the AC to 6V AC output Stepdown transformer is used. 6V AC supply from the secondary winding of step down transformer is directly applied to the Bridge Rectifier of the module, you can use either the bridge rectifier module and four 1N4007 diodes in bridge rectifier form. Here the 6V AC is Converted into a 6V DC supply then this unfiltered DC is applied to the filter of the capacitor C1 and then filtered DC is applied to the Regulator IC LM317 (Package To-220) this IC has three terminals, terminal 1 (Adjust), and terminal 2 (output) are connected with feedback Resistor R1 and R2, by Varying these two Resistors value we could get our desired output voltage from 1.25V to 37V (if we apply enough input voltage to the terminal 3) and output current flow up to 1.5 Amps.

Power Supply Management Integrated Circuit (PMIC) for Complex Electronic Circuits to Supply Required Power. If we Design a simple Standalone circuit diagram with few low-power electronic components then we need an Individual Standalone power source or Voltage Regulator circuit diagram. Here Simple 1.5V DC Power Supply Circuit diagram was designed by using IC LM317 to give a Regulated Constant 1.5V DC power supply.

Eaton Power Supply Modules (EPM) offer a full line of Non-Isolated and Isolated DC-DC converters with a wide power supply rating from 1-60W. EPM has higher efficiencies than popular linear regulators or standard DC-DC converters in the market. Our Non-Isolated EPM (EPM78Vx and EPM12V) come in single output configurations featuring short circuit diagram protection.

Our EPM12V is also the programmable. Our Isolated EPM consists of 5 families (EPM6-1V and 2V, EPM7-1V, EPM25-1V 15W and 30W, and EPM25-2V 40W and 60W) in compact, through-hole SIP or SMT DOSA packages. Isolated EPM features a wide input voltage range, lower power supply consumption, and high isolation of the voltages up to 4kV in single and dual output configurations.

Frequently Asked Questions

How to reduce 12v to 1.5 V?

Using a step-down transformer 12 V could be cut down to 1.5 V. In a step-down transformer number of turns in the secondary of the secondary windings is less than the number of turns in the primary windings.

Can I use 5V for 3.7 V?

Charging a 3.7V lithium-ion battery with a 5V charger could potentially lead to overcharging and, in turn, damage the battery and, in extreme cases, cause a safety hazard. Lithium-ion batteries have specific voltage ranges for charging and discharging to ensure the safety of an operation.

What resistor to drop 5V to 1.5V?

Conceptually, put a 3.7 ohm a 5–3.7 = 1.3-ohm resistor in series, with the 1.3-ohm resistor connected to the +5 V supply, or the 3.7-ohm resistor connected to ground (the - connection on the 5V supply).

What is the full voltage of a 3.7 V battery?

The maximum voltage your 3.7V lithium-ion battery could have is 4.2V, also known as the maximum safe voltage/charge cut-off Voltage.

How to convert 3.7 volts to 5 volts?

So you cannot use 3.7V and 3.6V batteries even if you use two 3.7V batteries (3.7×2=7.4V) and four 1.2V batteries (1.2×4=4.8V). Hence you need a small DC-to-DC converter to get 5V, 6V, or both of these, depending on the intended of the application. The converter described here provides a simple solution an MC34063A IC.

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